x^2+44x-192=0

Solution for x^2+44x-192=0 equation:

x^2+44x-192=0

a = 1; b = 44; c = -192;
Δ = b2-4ac
Δ = 442-4·1·(-192)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-52}{2*1}=\frac{-96}{2}
=-48
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+52}{2*1}=\frac{8}{2}
=4
$